Oxygen (o) has 6 valence electrons, but there are 3 oxygen atoms in the borate ion, so total valence electrons from oxygen = 6 * 3 = 18. **steric number = number of sigma bonds + number. As a result, the three oxygen atoms form a sigma bond with the boron, which is the central atom.
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Hybridisation in chemistry is the process where atomic orbitals (usually s, p, and sometimes d orbitals of the same atom) mix to form new, equivalent hybrid orbitals.
On the other hand, every oxygen atom in boric acid is sp3 hybridized.
We determine this by calculating the steric number (sn). Process of combining two or more atomic orbitals from the same atom to form an entirely new different orbital from its components is called hybridisation. One orbital bonds the boron atoms to all three oxygen atoms in a double y shape — one y on each side of the molecular plane. Understanding the hybridization state of both the boron and oxygen atoms is key to grasping its molecular structure and chemical behavior.
The shape of the molecule so. Two orbitals are nonbonding because they have electron. These hybrid orbitals are better.
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