这方程等价于 y ″ i y = i (y i y) 其中 i 是 虚数单位。 若置 φ = φ (x):= y i y, 则有 φ = i φ 解得 y i y = φ = c e i x 两端同时乘上 e i x, 得 (e i x y) = c e 2 i x 积分即得 e i x y = 1 2 i c e 2 i x + c 1 于是 y = 1 2 i c e i. 拯救者y9000p至尊版~legion pro 7i； 拯救者y7000p~legion 5i; 关于方程 y 2 = x 3 k 2 的正整数解问题，这是一个典型的椭圆曲线方程（属于莫德尔方程的一种特殊形式），其解的存在性和数量与 k 的取值密切相关。以下从数学性质、已知结论和计算方法三个方面展开.
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